(x-5)(2x^2-7x-2)=0

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Solution for (x-5)(2x^2-7x-2)=0 equation:


Simplifying
(x + -5)(2x2 + -7x + -2) = 0

Reorder the terms:
(-5 + x)(2x2 + -7x + -2) = 0

Reorder the terms:
(-5 + x)(-2 + -7x + 2x2) = 0

Multiply (-5 + x) * (-2 + -7x + 2x2)
(-5(-2 + -7x + 2x2) + x(-2 + -7x + 2x2)) = 0
((-2 * -5 + -7x * -5 + 2x2 * -5) + x(-2 + -7x + 2x2)) = 0
((10 + 35x + -10x2) + x(-2 + -7x + 2x2)) = 0
(10 + 35x + -10x2 + (-2 * x + -7x * x + 2x2 * x)) = 0
(10 + 35x + -10x2 + (-2x + -7x2 + 2x3)) = 0

Reorder the terms:
(10 + 35x + -2x + -10x2 + -7x2 + 2x3) = 0

Combine like terms: 35x + -2x = 33x
(10 + 33x + -10x2 + -7x2 + 2x3) = 0

Combine like terms: -10x2 + -7x2 = -17x2
(10 + 33x + -17x2 + 2x3) = 0

Solving
10 + 33x + -17x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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